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Old 12-07-2012, 08:04 PM   #62
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Originally Posted by apollo_gnomon View Post
Y'all are using the wrong figures here. Stoich is 14.7:1 air:fuel, but measured by WEIGHT (actually, molecular weight, but weight is close enough) and 1/15 is not 15% but .067%. {14.7:1 gives .068**

Weight of air at daytime temperatures:
Let's call it 25c, giving a density of 1.184 kg/m^3. A cubit meter is 1000 litres, so that's 1.184g/litre.

Gasoline has a density of 44.9 lbs/ft^3 = 737.2g/litre.

0.068 (grams of fuel per 1g air ) x 1.184g (weight of 1litre air) = 0.080512g fuel = 0.0001092 litres of fuel per cylinder per intake stroke.

Maybe that will make more sense.
Cheers apollo.

You can get some real world figures using that example.

I've come across moles regarding calculating this - I'm steering clear, just thought their might be a simple way to get a handle on these Hydrogen on demand and HHO devices by comparing volume of gas they produce to to volume of fuel and air to work out how much is required to make gains or completely power the engine.

Rule of thumb so to speak.
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